Question

SISSE
A charge of 4 uC is moved from a point of -10 V to a point where potential is 30 V. The work done in doing so is​

Answer 1

Given:

A charge of 4 uC is moved from a point of -10 V to a point where potential is 30 V.

To find:

Work done ?

Calculation:

Potential Difference refers to the work done to move a unit positive charge from one place to another in a uniform electric field.

$\rm \: \Delta V = \dfrac{W}{q}$

$\rm \: \implies W = q \times \Delta V$

$\rm \: \implies W = (4 \times {10}^{ - 6} ) \times \{30 - ( - 10) \}$

$\rm \: \implies W = (4 \times {10}^{ - 6} ) \times 40$

$\rm \: \implies W = 160 \times {10}^{ - 6} \: J$

$\rm \: \implies W = 160 \: \mu J$

So, work done is 160 micro-Joule.

Answer 2

$\LARGE{\underline{\tt Solution:-}}$

Here

• q=4uC
• V1=-10V
• V2=30V

$\\ \tt\bull\rightarrowtail ∆V=V_2-V_1$

$\\ \tt\bull\rightarrowtail ∆V=30-(-10)$

$\\ \tt\bull\rightarrowtail ∆V=30+10$

$\\ \tt\bull\rightarrowtail ∆V=40$

we know that

$\boxed{\sf ∆V=\dfrac{W}{q}}$

$\\ \tt\bull\rightarrowtail W=∆V\times q$

$\\ \tt\bull\rightarrowtail W=40\times 4uC$

$\\ \tt\bull\rightarrowtail W=40\times (4\times 10^{-6})$

$\\ \tt\bull\rightarrowtail W=160\times 10^{-6} J$

$\\ \tt\bull\rightarrowtail \boxed{\bf{Work\:Done=160\boldsymbol{\mu} J}}$