sita can diposit 3000 rs with interests 10 % for 2 year then what was it's compound semi annual
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A = P( 1 + r/n)^nt
where n is the number of compounding a year
⇒A = 3000(1 + 0.1/2)^(2×2)
= 3000× (1.05)^4
= 3646.52
CI = Rs (3646.52 - 3000) = Rs 646.52
where n is the number of compounding a year
⇒A = 3000(1 + 0.1/2)^(2×2)
= 3000× (1.05)^4
= 3646.52
CI = Rs (3646.52 - 3000) = Rs 646.52
Hardikagrawal:
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Answered by
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principal=3000rs
interest=10% compounded semi annually
time =2yrs
amount=p(1+r/200)^2t
=3000(1+10/200)^4
=3000*21/20*21/20*21/20*21/20
=3000*194481/160000
=3654.02
compound interest =amount - principal
= 3654.02-3000
=654.02 ans
interest=10% compounded semi annually
time =2yrs
amount=p(1+r/200)^2t
=3000(1+10/200)^4
=3000*21/20*21/20*21/20*21/20
=3000*194481/160000
=3654.02
compound interest =amount - principal
= 3654.02-3000
=654.02 ans
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