Question

Sita is 3 years older than Geeta. 6 years ago, Sita's age was four times that of Geeta's age. Find the present age of Sita and Gita.​

Answer 1

Answer:

I really don't know this answer

Answer 2

Step-by-step explanation:

Given :-

Sita is 3 years older than Geeta. 6 years ago, Sita's age was four times that of Geeta's age.

To find :-

Find the present age of Sita and Gita ?

Solution :-

Let the present age of Gita be X years

Then,

The present age of Sita

= age of Gita +3 years

=> (X+3) years

Age of Sita in 6 years ago

= (X+3-6) years

=>( X-3 ) years

Age of Gita in 6 years ago = (X-6) years

Given that :

6 years ago, Sita's age was four times that of Gita's age

=> X-3 = 4(X-6)

=> X-3 = 4X-24

=> X-4X = -24+3

=> -3X = -21

=> 3X = 21

=> X = 21/3

=> X = 7 years

Gita's present age = 7 years

Sita's present age = X+3 years

= 7+3 years

= 10 years

Answer :-

The present age of Sita = 10 years

The present age of Gita = 7 years

Check:-

The present age of Gita = 7 years

The present age of Sita = 10 years

=> 7+3 years

=> Sita is 3 years older than Geeta

7 years ago their ages will be 7-6 = 1 year and

10-6 = 4 years

=> Sita's age = 4 years

=>4×1 years

=> 4×Gita's age

=> 4 times Gita's age

6 years ago, Sita's age was four times that of Geeta's age

Verified the given relations in the given problem.