Question

Sita sold two mobile set for24000 each she made a profit20% on one and loss of 20% on other. What was her profit or loss percent

Answer 1

GIVEN :-

• Sita sold to mobile set for 24000 each.
• in 1st mobile phone she had Profit of 20%.
• in another Mobile phone she had Loss of 20%

TO FIND :-

• The Profit or Loss %

SOLUTION :-

CASE 1,

⇒ S.P = 24000

⇒ Profit % = 20%

⇒ C.P = (S.P × 100)/(100 + P%)

⇒ (24000 × 100)/(100 + 20)

⇒ (24000 × 100)/120

⇒ 200 × 100

⇒ 20000

Hence C.P = 20000

CASE 2,

⇒ S.P = 24000

⇒ Loss % = 20%

⇒ C.P = (S.P × 100)/(100 - loss%)

⇒ (24000 × 100)/(100 - 20)

⇒ (24000 × 100)/80

⇒ 6000 × 5

⇒ 30000

Hence C.P = 30000

⇒ Total C.P = 30000 + 20000

⇒ 50000

⇒ Total S.P = 24000 + 24000

⇒ 48000

Now, C.P > S.P

⇒ Loss = C.P - S.P

⇒ 50000 - 48000

⇒ 2000

⇒ Loss % = [Loss/C.P × 100%]

⇒ [2000/50000 × 100%]

⇒ 4 %

Hence loss % is 4 %.

Answer 2

Her loss Percentage is 4% .

Given :-

• Sita sold two mobile set for Rs. 24000.
• In first mobile phone she made a profit of 20%.
• And in another mobile phone she made a loss of 20% .

To Find :-

• Calculate her profit or loss percentage.

Solution :-

Condition (1) :-

• SP = Rs. 24000
• Profit percent = 20%

As we know that,

=> CP = ( SP × 100)/(100 + Profit %)

=> CP = (24000×100) / (100 + 20%)

=> CP = 24000 × 100 / 120

=> CP = 20000 .

Condition (2) :-

• CP = Rs.20000
• Loss percent = 20%

We know that,

=> CP = ( SP × 100)/(100 - loss %)

=> CP = (24000 × 100)/(100-20)

=> CP = 24000 × 100 / 80

=> CP = 30000 .

Hence,

• Total CP = 30000 + 20000 = Rs.50000
• Total SP = 24000 + 24000 = Rs. 48000

.°. CP > SP

=> Loss = CP - SP

=> Loss =Rs.(50000 - 48000)

=> Loss = Rs.2000

.°. Loss % = ( Loss / CP × 100% )

=> Loss % = 2000/50000 × 100%

=> Loss% = 4 %