Sita takes twice as much time as Gita to complete a work and Rita does it in the same time as Sita and Gita together if all three working together can finish the work in 6 days then the time taken by each of them to finish the work is
Answers
Answer:
Step-by-step explanation:
Let Say Gita Complete a work in G Days
Sita will complete work in 2G days
Gita's 1 day work = 1/G
Sita's 1 day work = 1/2G
Sita + Gita together 1 day work = 1/G + 1/2G = 3/2G
Rita 1 day work = 3/2G
Rita complete work in 2G/3 Days
Sita + Gita + Rita together 1 day work = 1/G + 1/2G + 3/2G = 3/G
Sita + Gita + Rita together will complete work in G/3 days
G/3 = 6
=> G = 18 Days
Gita complete work in 18 Days
Sita Complete work in 2*18 = 36 Days
Rita complete work in 2*18/3 = 12 Days
Sita = 36 days
Gita = 18 days
Rita = 12 days
To find:
Sita = ?
Gita = ?
Rita = ?
Given data:
Sita takes twice as much time as Gita to complete a work i.e., s = 2g
Rita does it in the same time as Sita and Gita together i.e., r = s + g
all three working together can finish the work i.e., s + g + r = 6
Solution:
let the value g = 3x
and so s = 6x
then the value of r will be
r =
=
r = or 2x
all three working together can finish the work i.e.,
s + g + r = 6
in the above given equation substitute x value starting from 1
then by substituting x = 6 we get,
=
=
taking LCM we get
=
=
=
thus LHS = RHS
then Sita = 36 days
Gita = 18 days
Rita = 12 days
To solve more:
1. If 15 oxen or 20 cows can eat the grass of a field in 80 days, then in how many days will 6 oxen and 2 cows eat the same grass?
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2. A can do a piece of work in 20 days and b can do it in 25 days .both of them finished the work and earned rs.3600.then a's share is?
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