Math, asked by greeshu81, 10 months ago

siva, solomon and suresh can complete the work in 12,20 and 15 days respectively. Solomon and Suresh support siva every alternative day. when will the work be finished (approx) on days?​

Answers

Answered by sushant2586
0

Answer:

Work willbe finished approximately in 8 days

Step-by-step explanation:

Siva, solomon and surech completes the work in 12 days, 20 days and 15 days respectively.

Thus in one sigle day,

Work done by siva = Wsi = 1/12

Work done by solomon = Wso = 1/20

Work done by suresh = Wsu = 1/15

Siva is working daily, and solomon and suresh works in alternate days.

Thus we will find the work completed in 1st two days.

In 2 days, siva will complete 1/12 + 1/12 of the work

Solomon will work 1 day 1/20

and suresh will work one day 1/15

∴Total work completed in two days = 1/12 + 1/12 + 1/20 + 1/15

∴Total work completed in two days = (5 + 5 + 3 + 4 ) / 60

∴Total work completed in two days = 17 / 60

Thus in six days work done = 3 * work done in two days.

Work done in 6 days = 3 * 17/60 = 51/60

Remaining work = 60/60 - 51/60 = 9/60

On 7th day siva and solomon will work togather.

Work doen on 7th day = 1/12 + 1/20 = (5 + 3) / 60 = 8/60

Thus work pending after 7th day = 9/60 - 8/60 = 1/60

On 8th day, work dane by siva and suresh togather  = 1/12 + 1/15 = 9/60

But as the pending work is only 1/60, work will be completed on 8th day.

Total work will be finished in (approx) 8 days

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