Question

Six bags of cement, each marked 10 kg, actually contained the following weights of cement (in kg): 10.1, 9.95, 10.4, 9.93, 10.8, 10.0 Find the probability that any of these bags chosen at random contains less than 10 kg of cement.

A) 1/2
B) 1/3
C) 2/3
D) 1/6

Answer 1

$\underline{\boxed{\bold{Question}}}$

• Six bags of cement, each marked 10 kg, actually contained the following weights of cement (in kg): 10.1, 9.95, 10.4, 9.93, 10.8, 10.0.

• Find the probability that any of these bags chosen at random contains less than 10 kg of cement.

$\underline{\boxed{\bold{Answer}}}$

Favorable event = Bags marked with less than 10 kg

                            = 2 (9.95 , 9,93)

Total events = 6 (10.1, 9.95, 10.4, 9.93, 10.8, 10.0)

${\boxed{\bold{\therefore Probability = \frac{Favorable \:Event}{Total \:Event} }}}$

∴ Probability = 2/6 = 1/3

${\boxed{\bold{Correct \:Option = B] \frac{1}{3} }}}$

Hope this helps u.../

【Brainly Advisor】

Answer 2

Answer:

Question

Six bags of cement, each marked 10 kg, actually contained the following weights of cement (in kg): 10.1, 9.95, 10.4, 9.93, 10.8, 10.0.

Find the probability that any of these bags chosen at random contains less than 10 kg of cement.

\underline{\boxed{\bold{Answer}}}

Answer

Favorable event = Bags marked with less than 10 kg

= 2 (9.95 , 9,93)

Total events = 6 (10.1, 9.95, 10.4, 9.93, 10.8, 10.0)

{\boxed{\bold{\therefore Probability = \frac{Favorable \:Event}{Total \:Event} }}}

∴Probability=

TotalEvent

FavorableEvent

∴ Probability = 2/6 = 1/3

{\boxed{\bold{Correct \:Option = B] \frac{1}{3} }}}

CorrectOption=B]

3

1

Hope this helps u.../

【Brainly Advisor】