Six coins are tossed. find the probability of at least 2 heads
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Probability of at least 2 heads is
1. The probability of all tail
= 1 / 64
2. The probability of single head
[(6*5*4*3*2*1) / 2 (4*3*2*1)] / (6*5*4*3*2*1)
15 / 64
By (1) & (2) we get
16/64
= 4/16
= 1/4
Therefore, probability of at least 2 heads
1 - (1/4) = 3/4.
1. The probability of all tail
= 1 / 64
2. The probability of single head
[(6*5*4*3*2*1) / 2 (4*3*2*1)] / (6*5*4*3*2*1)
15 / 64
By (1) & (2) we get
16/64
= 4/16
= 1/4
Therefore, probability of at least 2 heads
1 - (1/4) = 3/4.
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