Six dice are stacked on the floor as shown in the figure. On each dice the sum of numbers on opposite face is 7 i.e if one is written on one face then 6 is written on the opposite face and so on.
What is the maximum possible sum of numbers on the 21 visible faces.
Attachments:
Answers
Answered by
31
❏ Question:-
@ Six dice are stacked on the floor as shown in the figure. On each dice the sum of numbers on opposite face is 7 i.e if one is written on one face then 6 is written on the opposite face and so on.What is the maximum possible sum of numbers on the 21 visible faces.
❏ Solution:-
✏ Given:-
- six dice are stacked on the floor,
- On each dice the sum of numbers on opposite face is 7
( i.e if one is written on one face then 6 is written on the opposite face )
✏ To Find:-
- maximum possible sum of numbers on the 21 visible faces.
✏ Explanation :-
Now,
- Sum of numbers on top dice
✏ 6 + 2×(sum of opposite faces)
✏ 6 + 2×(7)
✏ 6 + 14
✏ 20
- Sum of numbers on left side dice in the middle position
✏ 6 + 1× (sum of opposite faces)
✏ 6 + 1×7
✏ 6+7
✏ 13
- Sum of numbers on right side dice in the middle position
✏ 6 + 1×( sum of opposite sides)
✏ 6 + 1×7
✏ 6 + 7
✏ 13
- Sum of numbers on right side dice in the bottom position
✏ 6 + 5 + sum of opposite faces
✏ 11 + 7
✏ 18
- Sum of numbers of middle dice in the bottom position
✏ sum of opposite faces
✏ 7
- Sum of numbers on left side dice in the bottom position
✏ 6 + 5 + sum of opposite faces
✏ 11 + 7
✏ 18
∴ Total sum
= 20 + 13 + 13 + 18 + 7 + 18
= 89
Answered by
8
Similar questions
Social Sciences,
5 months ago
Math,
5 months ago
Physics,
5 months ago
Science,
9 months ago
Math,
9 months ago
Social Sciences,
1 year ago
Math,
1 year ago
Math,
1 year ago