Six diesel engines consume 900 liters of diesel, when each one is running for 5 hrs a day. How much diesel will be required by 9 engines, each running 8 hrs a day when 5 diesel engines of former type consume as much diesel as 8 diesel engines of the latter type?
Answers
Answered by
0
Answer:
2160 liter diesel
Step-by-step explanation:
Total running time =6X5=30 HRS
required disel for running a engine 1 hr=900/30=30liter
Total running time with new engine=9X8=72hrs
Required diesel =72X30=2160liter
Answered by
0
Answer:
1350
Step-by-step explanation:
one Former diesel engine , one hour consumption =
900/ (5*6) = 30 lrs.
ATQ
consumption of 5 former engine = consumption of 8 latter engines
therefore
(consumption of 1 former engine)*5 = consumption of 8 latter engine
consumption of 8 latter engine for one hour =5*30 = 150
therefore consumption of 9 latter engine for 8 hours is = (150*9*8)/8 = 1350
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