Question

Six marbles having equal radius
touching one another as shown in the
figure .the volume of each marble is 9pi/2
cm3. Find the
distance from P to Q.​

Answer 1

Answer:

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Answer 2

Answer:

Volume of Sphere =

$\: 4 \div 3\pi \: r ^{3}$

$9 \div 2\pi \: = \: 4 \div 3\pi \: r ^{3}$

π cancels out

$\:9 \div 2 = \: 4 \div 3 \: r ^{3}$

Transferring 4/3 to the other side

$(9 \div 2) \times (3 \div 4) = {r}^{3}$

Solving the LHS

$27 \div 8 = {r}^{3}$

Transferring the power to the other side

$\ \sqrt[3] {27 \div 8} = r$

$3 \div 2 = r$

Radius of Marble = 3/2 cm

Distance from P to Q =

6*Diameter of One Marble

= 6*(2*3/2)

Two cancels out

= 6*3

= 18 cm