Six papers are set in an examination, of which two are Mathematics. In how many different orders can the papers be arranged so that the two are not together?
This is a problem of Permutation and Combination. Please solve this problem step by step, as i could not solve it .
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Given that there are 6 papers
two mathematics papers =1 unit
the 2 papers can be arranged in remaining 4 places in 5p4 ways
the 2 papers can be arranged among themselves in 2! ways
total number of arrangements = 5p4 × 2! ways
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