Question

Six particles situated at the corners of a regular hexas
of side a move at a constant speed v. Each particle
maintains a direction towards the particle at the next
corner. Calculate the time the particles will take to meet
each other.


Explain each step.
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Answer 1

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Initial Separation = a ___________[given]

Final separation = 0____________[given]

So, the Relative displacement between two particles= a..

In QUESTION. Particle 'B' has a Component 'v' Cos 600 along with particle BC.

Therefore Relative velocity with which 'B' amd 'C' approaches each other..

= v-vcos60

= v/2

Since, V is constant, thus time take by these two balls to meet each other is given by :---

Formula = (Relative displacement)÷Relative velocity...

= a÷(v/2) = 2a/v..====== ANSWER.....

Answer 2

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Initial Separation = a ___________[given]

Final separation = 0____________[given]

So, the Relative displacement between two particles= a..

In QUESTION. Particle 'B' has a Component 'v' Cos 600 along with particle BC.

Therefore Relative velocity with which 'B' amd 'C' approaches each other..

= v-vcos60

= v/2

Since, V is constant, thus time take by these two balls to meet each other is given by :---

Formula = (Relative displacement)÷Relative velocity...

= a÷(v/2) = 2a/v..====== ANSWER.....