Question

Six paving stones are arranged in a square array as shown in the figure. If each stone
has a length 20 cm greater than its width, find
(a) the dimensions of each stone,
(b) the area of the ground space that the stones are occupying,
(c) the perimeter of the same ground space.​

Answer 1

Answer:

Solution:- The dimensions of a stone are x & 2x+20

width = x and length =x+20

one side of the square formed by the six stones =3x

and the other side = 2(x+20)=2x+40

Then 3x=2x+40➡ 3x-2x=40 ➡x=40 ;

So (a) The dimensions of each are x=40cm, x+20= 40+20=60cm...❗

(b) The area of the ground space =6(40×60)=6×2400

=14400sq.cm ie. 1.44sq.meters....‼

(cl The perimeter of the ground space = 2(3×40+2×60)↩

➡2(120+120)=2×240=480cm➡4.8 meters //