Question

Six year before, the age of mother was equal to the square of her son's

age. Three year hence, her age will be thrice the age of her son then.

Find the present ages of the mother and son. ​

Answer 1

Answer: son age 12

               mother age 42

Step-by-step explanation:

let the son age be s and mother age be m

m-6 = (s-6)^2

m+3=  3(s+3)

subtract those equations

-9 = s^2 -12s +36 -3s -9

s^2 -15s +36 =0

==> s(s-3) -12 (s-3) = 0

s-12)(s-3) = 0

==> s= 12

==> m= 42