Six years hence a man’s age will be three times his son’s age, and three years ago he was nine times as old as his son at that time. Find their present ages.
Answers
answer: Let the age of man be x
and the age of his son be y
According to the question:
After 6 years :
(x+6)=3(y+6)
⇒x−3y=12⟶(i)
Three years ago :
x−3=9(y−3)
⇒x−3=9y−27
⇒x−9y=−24⟶(ii)
Solving (i) and (ii),
6y=36
⇒y=6
Putting value of y in equation (i),
x−3xy=12
∴x=12+18
x=30
∴ Age of man =30 years.
Age of son =6 years.
Answer:
✒ Question:
✒ To find:
✒ Taken:
Let the age man be x
And
Let the age of the son be y
A/Q:
• After 6 years : (Equation 1)
Taken the equation as
(x+6)=3(y+6)
• Then , after 3 years ago : (Equation 2)
Taken the equation as
x-3=9(y-3)
• After that solve the equation 1 and 2
• At last find the age of both man and his son.
✒ Concept:
▪︎First find the answer of the equation 1.
▪︎Then find the answer of the equation 2.
▪︎Then solve both equation at a time.
▪︎The age of the son will come.
▪︎Then find the age of the man.
✒ Solution:
After 6 years:
=> x+6=3y+18
=> x-3y=18-6
=> x-3y=12
__________________________________
After 3 years:
=> x-3=9y-27
=> x-9y=-27+3
=> x-9y=-24
__________________________________
Solving equation 1 and equation 2:
=> -3y-(-9y)=12-(-24)
=> -3y+9y=12+24
=> 6y=36
=> y=36/6
=> y=6
__________________________________
Now , age of the man by taking y at equation 1:
=> x-3xy=12
=> x-3(6)=12
=> x-18=12
=> x=12+18
=> x=30
✒ Answer:
Age of the man = 30 years
Age of his son = 6 years
✒ Extra information:
In the answer :
Cross multiplication is used :
For example :
= 3(4)
= So , there will be 3 × 4
= 12
HOPE IT HELPS YOU