Size of the image of an object by a concave lens of focal length
20 cm is observed to be reduced to a rd of its size. Find the distance
of the object from the lens.
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Answer: The distance of the object is 40 cm from the lens.
Explanation:
Given that,
Focal length f = -20 cm
Magnification m =\dfrac{1}{3}
We know that,
The magnification is
m = \dfrac{v}{u}
\dfrac{1}{3}=\dfrac{v}{u}
u = 3v......(I)
Using lens formula
\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}
\dfrac{1}{-20}=\dfrac{1}{v}-\dfrac{1}{3v}
v = \dfrac{-40}{3}
Put the value of v in equation (I)
u = -40\ cm
Hence, The distance of the object is 40 cm from the lens.
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