size of the image of an object by a concave lens of focal length 20 cm is observed to be reduced to 1/3rd of its size find the distance of the object from the lens
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As it is a concave lens image would be virtual so magnification is only positive
»m=1/3
»v/u=1/3
»u=3v
We know that
1/v-1/u=1/f
1/v-1/3v=1/-20
3/3v-1/3v=1/-20
2/3v=1/-20
V=-40/3 cm
3V=U
U=-40 cm
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