Question

Sketch a parallelogram ABCD, ∠BAC = 56°, ∠BCD = 70°, Calculate and label ∠CBA and ∠ACB.

Answer 1

Answer:

hope this will help!!!!

Answer 2

Hey dear here is your answer

∠BAC= 56°

∠BCD= 76°

To find : ∠CBA & ∠ACB

Solution :

∠BAC= ∠ACD (alternate interior angles)

∠BCD= ∠ACB+∠ACD

= 70° = ∠ACB + 56°

∠ACB = 14°

∠ACB + ∠BAC + ∠CBA = 180°( angle sum property)

14°+ 56° + ∠CBA = 180°

∠CBA  = 180 - 70

∠CBA = 110°

hope it helps