slit for a
In Young's double slit experiment the slit seperation
is 1mm and the screen is 1m from the slit for a
monochromatic light of wavelength 500nm,the
distance of 3rd
minima is
Answers
Answered by
92
In Young's double-slit experiment the slit separation is 1mm.
(silt separation = d = 1 mm)
{ 1 mm = 1 × 10-³ m }
Also given that, separation from the screen from the slit is 1 m.
(D = 1 m)
Monochromatic light of wavelength 500 nm.
( = 500 nm)
{ 500 nm = 500 × 10^(-9) m }
Now,
We have to find the distance of 3rd minima.
(n = 3)
Substitute the known values
OR
BrainlyRaaz:
Perfect answer ❤️
Answered by
123
Given :-
• In Young's double slit experiment the slit separation is 1 mm.
• The screen is 1 m from the slit for a monochromatic light of wavelength 500 nm.
To find :-
The distance of the third minima().
Solution :-
Silt separation = d = 1 mm (given)
D = 1 m (given)
Wavelength given 500 nm = m.
• d = 1 nm =
• D = 1 m
• n = 3
We know,
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