Question

slope of normal to the curve y=2x^2+3​

Answer 1

Answer:

y=2x

2

+3sinx

dx

dy

=4x+3cosx

Thus slope of tangent at x=0 is 4(0)+3cos0=3

Hence slope of normal at the same point is −

m

1

=−

3

1

Step-by-step explanation:

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