Question

The digit in the tens place of a two-digit number is 3 more than the digit in the unit's place. Let the digit at units place be b. Then the number is:

2 points

10b + 30

11b + 3

11b + 30

10b + 3

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Answer 1

Answer:

ANSWER

Let the one's digit be y and tens digit be x,

Number = 10x + y

Then,x=3y⋯(i)

Reversed number = 10y + x

A.t.Q :- (10x+y)−(10y+x)=36 Put x = 3y in eq. (i)

⇒9x−9y=36

⇒x−y=4⋯(ii)

⇒3y−y=4

∴2y=4 x=3y ∴x=6

y=2

∴ Number = 62

Answer 2

Given :-

• A two digit number.
• Ten's place digit is 3 more than the unit's place digit.
• Digit at unit place is b.

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To Find :-

• What is the number ?

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Solution :-

As we know that

A two digit number is 10 × digit in ten’s place + digit in unit’s place.

➟ Ten's place digit = 3 more than b

➟ Ten's place digit = ( b + 3 )

Now the number will be

→ 10 × (ten's digit) + unit's digit

→ 10 × (b + 3) + b

→ 10b + 30 + b

→ 30 + 11b

Hence, the two digit number is 30 + 11b.