slove the following identities. cosx-cotx÷cosx+cotx=sinx-1÷sinx+1
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=> cosx-cosx/sinx
-----------------------=> cosxsinx-cosx/cosxsinx+cosx
cosx+cosx/sinx
By taking the common factor,
=> sinx-1/sinx+1..........
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Answered by
2
Answer:
Explanation:
cosx-cosx/sinx
=> cosxsinx-cosx/cosxsinx+cosx
cosx+cosx/sinx
By taking the common factor,
=> sinx-1/sinx+1..........
hi
its me @srivatsan
i am sorry, okay?
i did a mistake, and i accept it
please reply
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