Question

slove the linear equation 2x=5y +12 and 3x -2y +4=0 by substitution method

Answer 1

Answer:

x=-4

y=-4

Explanation:

2x=5y+12

or,x=(5y+12)/2---------1 no. equation

now,3x-2y+4=0

or,3 × {(5y+12)/2} -2y+4=0

or,{(15y+36)/2} -2y+4=0

or, {(15y+36)-(2y×2)}/2 = -4

or,(15y-4y)+36 = (-4)×2

or, 11y =(-8)-36

or,11y =(-44)

or,y=(-44)/11

or, y= -4

now, in the equation 1

x=(5y+12)/2

or,x= [{5×(-4)} + 12] / 2

or, x={(-20)+12}/2

or, x=(-8)/2

or,x=-4