Question

slove
the
pair of equation. 2/√x +3/√y=2 , 4/√x - 9/√y = -1​

Answer 1

Answer:

Let 1/√x be 'a' and 1/√y be 'b'

{2a + 3b = 2 }2       -        (1)                (Multiply by 2)

4a - 9b = -1         -        (2)

Solving equation (1) and (2) by elimination method

    4a + 6b = 4

-    4a - 9b = -1

    -    +         +

→         15b = 5

→           b = 1/3     -  (3)

 Subtituting value of b in equation (1)

→ 4a + 3(1/3) = 4

→ 4a = 4 - 3

→ a = 1/4

→ 1/√x = a

→ 1/√x = 1/4

→ √x = 4

→ x = 4²

→ x = 16

→ 1/√y = b

→ 1/√y = 1/3

→ √y = 3

→ y = 3²

→ y = 9

Hence, x = 16 and  y = 9

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Answer 2

Let 1/√x be 'a' and 1/√y be 'b'

{2a + 3b = 2 }2       -        (1)                (Multiply by 2)

4a - 9b = -1         -        (2)

Solving equation (1) and (2) by elimination method

   4a + 6b = 4

-    4a - 9b = -1

   -    +         +

→         15b = 5

→           b = 1/3     -  (3)

 Subtituting value of b in equation (1)

→ 4a + 3(1/3) = 4

→ 4a = 4 - 3

→ a = 1/4

→ 1/√x = a

→ 1/√x = 1/4

→ √x = 4

→ x = 4²

→ x = 16

→ 1/√y = b

→ 1/√y = 1/3

→ √y = 3

→ y = 3²

→ y = 9

Hence, x = 16 and  y = 9

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