Math, asked by aryarishi, 11 months ago

slove this question.

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Answered by bedabrata85

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$</p><p><body bgcolor="green"></p><p>L.H.S.\\ = sin 2x + 2 sin 4x + sin 6x\\ = [sin 2x + sin 6x] + 2 sin 4x \\= 2 sin 4x cos (-2x) + 2 sin 4x\\ = 2 sin 4x cos2x + 2 sin 4x\\ = 2 sin 4x (cos 2x + 1) \\= 2 sin 4x (2 cos^{2}x -1 + 1) \\= 2 sin 4x (2 cos^{2}x) \\= 4cos^{2}x sin 4x =R.H.S</p><p></body></p><p>$

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