Question

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$y = x$

Answer 1

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2.) F = (9/5)C + 32
When C =30
then F = (9/5)×30+32
= 54 + 32
= 86
therefore, Required temperature = 86°F
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3.) F = 95 then
F = (9/5)C+32
95 = (9/5)C+32
(9/5)C = 95 ➖ 32
(9/5)C = 63
C = 63×5/9
C = 35
therefore, required temperature = 35°C
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4.) When C = 0
then F = (9/5)×0+32
= 0+32
= 32
therefore, Required temperature = 32°F
When F = 0, then
F = (9/5)C+32
0 = (9/5)C+32
(9/5)C = ➖ 32
C = ➖ 32×5/9 = ➖ 160/9
therefore, Required temperature = ➖ 160/9°C
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5.) Let the temperature be X numerically, then
F = (9/5)C+32
x = (9/5)x + 32
(9/5)x ➖ x = ➖ 32
(4/5)x = ➖ 32
x = ➖ 32×5/4
x = ➖ 40
therefore, Numerically value of required temperature = ➖ 40°C
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