Question

small block of mass 1 kg is released from a seat at X which is at a height of 15 m from the ground up blocks come down and reaches avoid travelling a Kavi path calculate the velocity of a block when it finally reaches y g = 10



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Answer 1

Explanation:

we know that the final velocity will be

v = (2gh)1/2

here,

g = 10 m/s2

h = 15

so,

v = (2x10x15)1/2

thus,

v = 17.32 m/s