Question

smaller diagonal BD of parallelogram ABCD is perpendicular to side Ab and CD show that AC2-BD2=4AB2

Answer 1

Given ABCD is a parallelogram
We know that diagonals of a parallelogram isect each other.
AO=12AC and BO=12BD
Given BD is perpendicular to AB.
So in triangle ABO, ∠ABO=90 degrees.
 By Pythagoras theorem,
AO2=BO2+AB2
AB2=AO2-BO2
AB2=(12AC)2-(12BD)2=14AC2-14BD2=14(AC2-BD2)
AC2-BD2=4AB2

Answer 2

Answer:

Step-by-step explanation: