Smallest number by which 670 must be multipled to get a perfect cube
Answers
Answered by
0
a3 + b3 = (a + b) × (a2 – ab + b2) ⇔ a3 = (a + b) × (a2 – ab + b2) – b3
With a = 670, b = 669 and the equivalence we get:
6703 = 1339 x (6702 – 670 × 669 + 6692) – 6693 = 1339 x (448900 – 448230 + 447561) – 299418309 = 1339 x 448231 – 299418309 = 300763000
With a = 670, b = 669 and the equivalence we get:
6703 = 1339 x (6702 – 670 × 669 + 6692) – 6693 = 1339 x (448900 – 448230 + 447561) – 299418309 = 1339 x 448231 – 299418309 = 300763000
Similar questions