Question

Sn +2 Na OH → Na2SnO 2 + H2




plz reply as soon as possible​

Answer 1

Answer

This is an oxidation-reduction (redox) reaction:

2 HI + 2 e- → 2 H0

(reduction)

Sn0 - 2 e- → SnII

(oxidation)

NaOH is an oxidizing agent, Sn is a reducing agent.

Answer 2

Answer:

Explanation:

BTW what to do in this question??

Chemistry is my favorite so I will describe this equation.

1. This equation is already balanced.

2. H is an oxidizing agent, Sn is a reducing agent.

3. NaOH is Sodium Hydroxide which is usually found in Caustic Soda. Na2SnO2 is Sodium Stannite.

4. This reaction is displacement reaction.

Hope this helps....Pls mark me Brainliest if you find this helpful...