sn = 3n²-5n then a12=
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Step-by-step explanation:
Given that
Therefore, we have
=> a1 + a2 + a3 + ........ n terms = 3n²-5n
Now, for n = 1
=>a1 = 3×1- 5×1 = 3 - 5 = -2
Now for n = 2
=>a1 + a2 = 3×4 - 5×2 = 12-10 = 2
=> -2 + a2 = 2
=> a2 = 2+2
=> a2 = 4
Therefore, common difference = d
=> d = 4-(-2)
=> d = 4+2
=> d = 6
.°. a12 = a1+(n-1)d = a1 + 11d
=> a12 = -12 + (11×6)
=> a12 = -12 + 66
=> a12 = 55
Hence, a12 = 55
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