Sn=3n²6n,
find
D
and
10th
term of AP
Answers
Answered by
1
Answer:
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Answered by
1
Answer:
d=6
a10=63
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Step-by step
Sn = 3n^2 + 6n
=> n/2 [ 2a + (n-1) d] = n (3n + 6)
=> [ 2a + (n-1) d] = 2 (3n +6)
=> 2a + (n-1) d = 6n + 12
=> 2a + (n-1)d = 18 + 6n - 6
=> 2a + (n-1)d = 18 + 6(n-1)
On Comparing both sides, we get
2a = 18
=> a = 9
And, d = 6
a10=a+(n-1)d
=9+9*6
=54+9
=63
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