Question

sneha is 4 times as old as her daughter. 2 years ago she was 5 times as old as her. what are there present age​

Answer 1

Given

Sneha is 4 times as old as her daughter. 2 years ago she was 5 times as old as her.

Find out

Find the present ages .

Solution

✞ Let the daughter age be x and Sneha age be 4x

• After 2 years
• Daughter's age = (x - 2) yrs
• Sneha's age = (4x - 2) yrs

$\bigstar\:\bf\underline{\purple{According\:to\:the\:given\:condition}}\:\bigstar \\ \\ \implies\tt (4x - 2)=5(x-2) \\ \\ \\ \implies\tt 4x -2=5x-10 \\ \\ \\ \implies\tt 5x-4x=10-2 \\ \\ \\ \:\:\therefore\tt \:\:x=8$

Hence,

• Present age of daughter = x = 8years

• Present age of Sneha = 4x = 32years

$\rule{200}3$

Answer 2

$\bf{\underline{\underline \blue{Solution:-}}}$

$\sf\underline{\red{\:\:\: AnswEr:-\:\:\:}}$

• Sneha's age = 32 years
• Daughter's age = 8 years

$\sf\underline{\red{\:\:\: Given:-\:\:\:}}$

• Sneha is 4 times as old as her daughter.
• 2 years ago she was 5 times as old as her.

$\sf\underline{\red{\:\:\: Need \:To \: Find:-\:\:\:}}$

• Sneha's present age = ?
• Daughter's present age = ?

$\bf{\underline{\underline \blue{Explanation:-}}}$

Let the present age of Sneha's daughter = Y years.

$\sf\underline{\red{\:\:\: ThereFore:-\:\:\:}}$

• Present age of Sneha = 4y

$\sf\underline{\red{\:\:\: 2\: Years\:ago,\:\:\:}}$

• Sneha's age = 4y - 2
• Sneha's daughter's age = y - 2

$\sf\underline{\green{\:\:\: A.T.Q:-\:\:\:}}$

$\dashrightarrow \sf {4y - 2 = 5(y-2)}$

$\dashrightarrow \sf {4y - 2 = 5y-10}$

$\dashrightarrow \sf {4y - 5y = - 10+2}$

$\dashrightarrow \sf { - y = - 8}$

$\dashrightarrow \sf {y = 8}$

$\sf\underline{\green{\:\:\: Thus:-\:\:\:}}$

• Sneha's age = 4 × 8 = 32 years
• Daughter's age = 8 years

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