Question

Sneha is 4 times as old as her daughter . two years ago ,she was 5 times as old as her .What are their present ages​

Answer 1

$\huge\mathfrak{Answer:}$

Let the present age of Sneha's daughter be x years.

$\therefore$Present age of Sneha=4x

2 years ago

Sneha's age=4x-2

Sneha's daughter's age=x-2

4x-2=5(x-2)

4x-2=5x-10

x=8

Sneha's age=4×8=32 years}

Daughter's age=8 years

Answer 2

solution:-

=>Let the present age of Sneha's daughter = x years.

therefore,

Present age of Sneha=4x

2 years ago,

Now,

Age of sneha =4x-2

Age of sneha's daughter=x-2

A/q,

=>4x-2=5(x-2)

=>4x-2=5x-10

=> 4x - 5x = - 10+2

=> - x = - 8

=> x = 8

Hence,

present age of daughter 8 years

present age of sneha 4x = 4 × 8 = 32 years

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