Sneha is 4 times as old as her daughter . two years ago ,she was 5 times as old as her .What are their present ages
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Let the present age of Sneha's daughter be x years.
Present age of Sneha=4x
2 years ago
Sneha's age=4x-2
Sneha's daughter's age=x-2
4x-2=5(x-2)
4x-2=5x-10
x=8
Sneha's age=4×8=32 years}
Daughter's age=8 years
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solution:-
=>Let the present age of Sneha's daughter = x years.
therefore,
Present age of Sneha=4x
2 years ago,
Now,
Age of sneha =4x-2
Age of sneha's daughter=x-2
A/q,
=>4x-2=5(x-2)
=>4x-2=5x-10
=> 4x - 5x = - 10+2
=> - x = - 8
=> x = 8
Hence,
present age of daughter 8 years
present age of sneha 4x = 4 × 8 = 32 years
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