Chemistry, asked by somac295, 3 months ago

So2+2H2S=2H2O+3S. Mention Oxidization and reduction

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Answered by Anonymous

3

Here, Hydrogen sulphide is oxidized to sulphur by removal of Hydrogen.

Sulphur dioxide is reduced to water by addition of hydrogen and removal of electronegative element sulphur.

Hence, Sulphur dioxide is the oxidizing agent and Hydrogen sulphide is the reducing agent.

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