So2 and he gases are present in 2:1 molar ratio in a closed vessel are allowed to effuse.the average molar mass of the initially effused gas mixture
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The molar ratio of gases coming out is 1:4
Explanation:
Rate of Effusion α speed α 1√M
M=molar mass
In the given question, mole ratio of He : SO2 = 1 :2
Molar mass of He = 4 g
Molar mass of SO2= 64 g
Number of moles = number of moles of substance/total number of moles
Mole ratio of He : SO2 = 1:2
Molar mass ratio of He : SO2 = 4 : 64 = 1 : 16
√Mass of He/Mass of SO2 = √4/64 = √ 1/16
Effusion rate of He/Effusion rate of SO2 = 1/4
Thus the molar ratio of gases coming out is 1:4
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