So2+H2S+H20 balance the equation
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We want to balance the equation 2+2=+2.
It can be seen that on the RHS, the number of hydrogen atoms is twice the number of oxygen atoms.
⇒ On the LHS the number of molecules of 2 should be twice the number of molecules of 2.
So, as an intermediate step, we tentatively put 2+22=+2.
Now we see that there are four atoms of hydrogen and two atoms of oxygen in the LHS.
⇒ We should have two molecules of water on the RHS.
So, we modify the equation to 2+22=+22.
Now there are three sulphur atoms on the LHS.
⇒ There should be three sulphur atoms on the RHS also.
So we get the balanced equation 2+22=3+22.
Explanation:
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