,, social Bandish question
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(3√2) /(√3+√6) = [ { (3√2) × (-√3+√6) } / {(√3+√6) × (-√3+√6)} ]
= (- 3√6 + 3√12)/(3) = √12 - √6 = 2√3 - √6.
(4√3) /(√2+√6) = [ { (4√3) × (-√2+√6) } / {(√2+√6) × (-√2+√6)} ]
= (- 4√6 + 4√18)/(4) = √18 - √6 = 3√2 - √6.
(√6) /(√3+√2) = [ { (√6) × (-√2+√3) } / {(√3 + √2) × (-√2+√3)} ]
= (- √12 + √18)/(1) = -√12 + √18 = 3√2 - 2√3.
So, (3√2) /(√3+√6) + (4√3) /(√2+√6) + (√6) /(√3+√2)
= 2√3 - √6. + 3√2 - √6. + 3√2 - 2√3.
= 6√2 - 2√6
hope it helped.....☺️
= (- 3√6 + 3√12)/(3) = √12 - √6 = 2√3 - √6.
(4√3) /(√2+√6) = [ { (4√3) × (-√2+√6) } / {(√2+√6) × (-√2+√6)} ]
= (- 4√6 + 4√18)/(4) = √18 - √6 = 3√2 - √6.
(√6) /(√3+√2) = [ { (√6) × (-√2+√3) } / {(√3 + √2) × (-√2+√3)} ]
= (- √12 + √18)/(1) = -√12 + √18 = 3√2 - 2√3.
So, (3√2) /(√3+√6) + (4√3) /(√2+√6) + (√6) /(√3+√2)
= 2√3 - √6. + 3√2 - √6. + 3√2 - 2√3.
= 6√2 - 2√6
hope it helped.....☺️
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Answer:
(3√2) /(√3+√6) = [ { (3√2) × (-√3+√6) } / {(√3+√6) × (-√3+√6)} ]
= (- 3√6 + 3√12)/(3) = √12 - √6 = 2√3 - √6.
(4√3) /(√2+√6) = [ { (4√3) × (-√2+√6) } / {(√2+√6) × (-√2+√6)} ]
= (- 4√6 + 4√18)/(4) = √18 - √6 = 3√2 - √6.
(√6) /(√3+√2) = [ { (√6) × (-√2+√3) } / {(√3 + √2) × (-√2+√3)} ]
= (- √12 + √18)/(1) = -√12 + √18 = 3√2 - 2√3.
So, (3√2) /(√3+√6) + (4√3) /(√2+√6) + (√6) /(√3+√2)
= 2√3 - √6. + 3√2 - √6. + 3√2 - 2√3.
= 6√2 - 2√6
hope it helped.....☺️
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