sodium Ion has completely filled with K and l shells explain
Answers
Answered by
5
Hey friend here is your answer . . . . .
The atomic number of sodium ( Na ) is 11 and it's electronic configuration is 2, 8, 1. Hence it will occupy K and L shell fully as per the 2n^2 rule of Bohr- Bury. According to this rule, the number of electrons in a shell is decided by putting the number of the shell in place of the alphabet ' n '. Eg : If we have to find out the number of electrons that would be in the second shell then by putting the value of n we will get : 2(2)^2 = 8 Thus, the number of electrons in the second shell is 8.
Hope it helps you !!!
The atomic number of sodium ( Na ) is 11 and it's electronic configuration is 2, 8, 1. Hence it will occupy K and L shell fully as per the 2n^2 rule of Bohr- Bury. According to this rule, the number of electrons in a shell is decided by putting the number of the shell in place of the alphabet ' n '. Eg : If we have to find out the number of electrons that would be in the second shell then by putting the value of n we will get : 2(2)^2 = 8 Thus, the number of electrons in the second shell is 8.
Hope it helps you !!!
yeshwanth68:
Thanx sis
Hii
Similar questions