Question

sodium metal crystallizes to form BCC structure the edge length of the unit cell is 4.29 into 10 raise to minus 8 cm calculate the radius of sodium atom​

Answer 1

Answer:

1.86 angstroms will be the radius of the sodium atom.

Explanation:

We know thar for the bcc lattice, the radius r is given by √3a/4 where a is the edge length of the given structure.

Since, in the question it is given that the edge length a of the unit cell is given by 4.29*10^-8 which can be written in 4.29 angstroms.

Hence, we get that the value of r after putting all the values as = √3 *4.29/4 = 1.73 * 4.29 angstroms/4 = 1.86 angstroms.

Answer 2

Explanation:

Sodium atom can be found in a periodic table as a chemical element. Its symbol is Na, which is a soft and silvery ‘reactive metal’. Sodium atom releases hydrogen when it decomposes while floating in the water. It belongs to the alkali metals which are found in abundance in nature.

Given Factor= a, the edge length of unit cell=4.29

To find the Value of Radius r

The radius of the sodium atom can be calculated with formula

$4 r=\sqrt{3} a$

$\mathrm{r}=\sqrt{3} \mathrm{a} / 4$

$r=\sqrt{3} * 4.29 / 4$

$\mathrm{r}=1.86 \mathrm{Armstong}$