Question

Sodium thiosulphate (Na2S2O3.5H2O) reacts with iodine as follows: 2S2O3^-2 + I^2 ----> S4O6^-2 + 2I^-1 . Calculate equivalent mass of sodium thiosulphate.

Answer 1

Answer:

2Na2S2O3 +I2 =2NaI +Na2S4O6

Here, oxidation no. of Na2S2O3 =+2

And Na2S4O6 =+2.5

Here, Na2S2O3 has 2 mole and sulphur is 4 then oxidation no. of Na2S2O3 is 4×2=8

In product side Na2S4O6 has 1 mole and sulphur element is 4 then the oxidation. No is 4×2.5=10

The difference of exchanged electron is 10-8=2

The equivalent weight of Na2S2O3 is = molecular weight of Na2S2O3/n factor

N factor= no of exchanged electron /no of moles

The equivalent weight of Na2S2O3=158×2/2=158

Answer 2

Answer:

248

Explanation:

Molecular mass of Na₂SO₃.5H₂O = 248

Charge on cation = 1

So , Equivalen mass = Mol. mass / charge on cation

= 248/1

= 248

Hope this helps . Please mark as brainliest.