Sodium zincate =Na2ZnO2 /H4Na2O4Zn
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When Zn reacts with NaOH it gives Na2ZnO2
When Zn reacts with NaOH + H20 it gives H4Na2O4Zn
Notice:
in Na2ZnO2 & H4Na2O4Zn the only diff is that that are 2 extra molecules of water in H4Na2O4Zn
Na2ZnO2 H4Na2O4Zn
1 Na 1 Na
1 Zn 1 Zn
2 O 4 O
0 H 4 H
So, H4Na2O4Zn has excess of 4 H and 2 O which is equal to 2 H2O.
Hope it helps.....
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