Question

sol it example..........​

Answer 1

Answer:

r= 4 cm

angle = 30

area of sector= π(r) 2¤/360

=3.14 x 4 x 4 x 30/360

= 12.56/3

= 4.19

area of major sector= π(r)2-area of minor sector

=( 3.14 x 16) - 4.19

= 50.24-4.19

=46.05

Answer 2

Answer:

r=4cm

thetha = 30

area of sector = thetha/360×πr^2

30/360×π(4)(4)

1/12×3.14×16

4.18666.....approx

Now area of major segment =

πr^2-area of sector

3.14×(4)(4)-4.186666...

46.053334approx