Math, asked by student8116, 11 months ago

sol it friends this qustion11

Attachments:

Answers

Answered by rishu6845
3

Answer:

plzzz give me brainliest ans and plzzzz follow me please

Attachments:
Answered by jitendra742
0

Answer:

tan60=AB/BC

√3=AB/BC

BC=AB/√3. (1)

tan30=AB/DB

tan30=AB/(20+BC)

form (1)....

1/√3=AB/(20+AB/√3)

20+AB/√3=√3AB

20√3+AB=3AB

3AB-AB=20√3

AB=10√3

AB=17.32

that is the hight of tower

Similar questions