solbe 3rd part of 4 question....no spamming
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Answer:(X+Y)+Z
iii)(X+Y)+Z=3/5+(-6/9+2/20)
=3/5+((-6/9×20/20)+(2/20×9/9))
=3/5+(-120/180+18/180)
=3/5+((-120+18)/180)
=3/5+(-102/180)
=(3/5×36/36)+(-102/180)
=108/180+(-102/180)
=(108+(-102))/180
=6/180
=1/30
X+(Y+Z)=(3/5+-6/9)+2/20
=((3/5×36/36)+(-6/9×20/20)+2/20
=(108/180+(-120/180))+2/20
=108+(-120)/180+2/20
=(-12/180)+2/20
=(-12/180)+(2/20×9/9)
=(-12/180)+18/180
=(-12+18)/180
=6/180
=1/30
Therefore,(X+Y)+Z=X+(Y+Z)(Proved)
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