Math, asked by priyaw8eetr1ad, 1 year ago

Solce for x: sin-1x=cos-1x a question from Inverse Trigonometry Functions

Answers

Answered by ARoy
0
sin⁻¹x=cos⁻¹x
or, sin⁻¹x=π/2-sin⁻¹x  [∵, sin⁻¹x+cos⁻¹x=π/2]
or, 2sin
⁻¹x=π/2
or, sin
⁻¹x=π/4
or, x=sin(
π/4)
or, x=1/
√2
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