Question

Sole it (Ans-11)..............​

Answer 1

$\huge\bf{\red{\overbrace{\underbrace{\purple{Given:}}}}}$

★n(A) =35.

★$n(A\cap B\cap C') =8$

★$n(A\cap C \cap B')=10$

★$n(A\cap B \ cap C') =6$

$\huge\bf{\red{\overbrace{\underbrace{\purple{To\:\:Find:}}}}}$

★$n(A\cap B \cap C)$

$\huge\bf{\red {\overbrace{\underbrace{\purple{Concept\:\:Used:}}}}}$

★We will be using "Venn diagram " for simplification.

$\huge\bf{\red {\overbrace{\underbrace{\purple{Answer:}}}}}$

We have,

★n(A) =35.

★$n(A\cap B\cap C') =8$

★$n(A\cap C \cap B')=10$

★$n(A\cap B \ cap C') =6$

________________________

On drawing Venn diagram it is clear that ,

$n(A\cap B \cap C)$

$\implies n(A\cap B \cap C)= 5-(8+6+10)$

$\implies n(A\cap B \cap C)= 35-24$

${\underline{\boxed{\red{ .\degree. n(A\cap B \cap C) =11}}}}$

Answer 2

Answer:

$\huge\boxed{\fcolorbox{red}{pink}{Your's Answer}}$

Given:-

n(A) =35.

★n(A\cap B\cap C') =8

★n(A\cap C\capB')=10

n(A∩B capC')=6

To find:-

★n(A\cap B \cap C)n(A∩B∩C)

We will be using "Venn diagram " for simplification.

Solution:-

We have,

★n(A) =35.

★n(A\cap B\cap C') =8n(A∩B∩C′)=8

★n(A\capC\capB')=10n(A∩C∩B′)=10★n(A\cap B \ cap C') =6n(A∩B capC′)=6

On drawing Venn diagram it is clear that ,

n(A\cap B \cap C)n(A∩B∩C)

\implies n(A\cap B \cap C)= 5-(8+6+10)⟹n(A∩B∩C)=5−(8+6+10)

\implies n(A\cap B \cap C)= 35-24⟹n(A∩B∩C)=35−24

n(A∩B∩C)= 11

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