Question

How do you find the area of a rectangle with sides 6a2b4 and 3ab2?

Answer 1

Given ,

Length , L = 6a²b⁴ Units

Breadth , B = 3ab² Units

So , Area = L*B = (6a²b⁴*3ab²) Sq. Units

=> Area = 18a^3b^6 Sq. Units

Answer 2

sides are 6a^2 b^2 and 3ab^2

area of rectangle = length × breadth

so, area = 6a^2 b^2 × 3ab^2

area = 18 a^2 b^2 a^1 b^2

area = 18 a^3 b^4 sq.unit

because power added when base is same