A diagonal of a square parking lot is 70 meters. How do you find, to the nearest meter, the length of a side of the lot?
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Let the square be ABCD .
So , Diagonal , AC = 70 m
Now , In rt. ∆ ABC ,
AC² = AB² + BC²
=> 70² m² = AB² + BC²
=> 70² m² = AB² + AB ² [ Since , ABCD is a square , So , AB = BC = CD = DA ]
=> 2(AB²) = 4900m²
=> AB² = 2450 m²
=> AB = √2450 m²
=> AB = 49.5 m .
So , Length of the side of lot = 49.5 m
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